AW: Re: Calculate the 20th of next month -- RPG400-L

Sorry I was wrong, I only read half of the message.

mydatefield = %date(20091031:*ISO)
%month(mydatefield) +=1;

MyDateField stays unchanged, i.e. it is still 20091031!
And %Month() on the left side of the equal sign is not allowed.

Mit freundlichen Grüßen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them
and keeping them!"

-----Ursprüngliche Nachricht-----
Von: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] Im
Auftrag von Birgitta Hauser
Gesendet: Tuesday, 06. October 2009 16:01
An: 'RPG programming on the IBM i / System i'
Betreff: AW: Re: Calculate the 20th of next month

No, 2009-11-30!

Mit freundlichen Grüßen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them
and keeping them!"

-----Ursprüngliche Nachricht-----
Von: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] Im
Auftrag von Jeff Crosby
Gesendet: Tuesday, 06. October 2009 15:46
An: RPG programming on the IBM i / System i
Betreff: Re: Re: Calculate the 20th of next month

Or this scenario:

mydatefield = %date(20091031:*ISO)
%month(mydatefield) +=1;

Now what's in mydatefield? 2009-12-01?

On Tue, Oct 6, 2009 at 9:00 AM, Anwendungsentwicklung <
Anwendungsentwicklung@xxxxxxxxxxxxxxxxxxxx> wrote:

And how does it work in december?
%month(mydatefield) = 12 --> += 1 ??? --> 13 ???
Or will it work correctly?

Susanne Finger

-----Ursprüngliche Nachricht-----
Von: rob@xxxxxxxxx [mailto:rob@xxxxxxxxx]
Gesendet: Dienstag, 6. Oktober 2009 14:43
An: RPG programming on the IBM i / System i
Betreff: Re: Calculate the 20th of next month

Anyone thought of submitting a DCR to be able to assign a date portion
from the left side of the equation? Like,
%month(mydatefield) +=1;
%day(mydatefield) = 20;

Does anything else think that
SomeDays = subdt(mydatefield:*days);
is more cryptic than
SomeDays = %day(mydatefield);

Or are they afraid that you'll get confused between %day and the
existing
%days as in
dueDate = SellDate + %days(TermDays);

Rob Berendt
--
Group Dekko Services, LLC
Dept 01.073
Dock 108
6928N 400E
Kendallville, IN 46755
http://www.dekko.com

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