|
mydatefield = %date(20091031:*ISO)
%month(mydatefield) +=1;
And how does it work in december?list
%month(mydatefield) = 12 --> += 1 ??? --> 13 ???
Or will it work correctly?
Susanne Finger
-----Ursprüngliche Nachricht-----
Von: rob@xxxxxxxxx [mailto:rob@xxxxxxxxx]
Gesendet: Dienstag, 6. Oktober 2009 14:43
An: RPG programming on the IBM i / System i
Betreff: Re: Calculate the 20th of next month
Anyone thought of submitting a DCR to be able to assign a date portion
from the left side of the equation? Like,
%month(mydatefield) +=1;
%day(mydatefield) = 20;
Does anything else think that
SomeDays = subdt(mydatefield:*days);
is more cryptic than
SomeDays = %day(mydatefield);
Or are they afraid that you'll get confused between %day and the
existing
%days as in
dueDate = SellDate + %days(TermDays);
Rob Berendt
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