Re: Bit Operation - BITAND

Hello,

I think you're confused with the literals, you use hexadecimal literal
as binary lietrals

what you're doing is
if %bitand(x'72':x'10') = x'10' // which gives true
if (b'01110010' and b'00010000') = b'00010000'
(if we had binary literals ;)

and what you whant to do is
if %bitand(x'72':x'80') = x'80' // which gives false
if (b'01110010' and b'10000000') = b'10000000'


nicolas


Michael Ryan a écrit :

Here's my lil' code segment:

D PrimaryBitMap...
D S 8A Inz(x'7224648008C08000')

/Free

If %BitAnd(%SubSt(PrimaryBitMap:1:1):x'10000000') = x'10000000';
dsply 'yes';
Else;
dsply 'no';
EndIf;

Since the first byte of PrimaryBitMap is x'01110020' (right?), it should
dsply 'yes'...but it dsplys 'no'. What am I doing wrong? Thanks!

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