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That makes sense, because the date part is equal. How about this:

D time1 S Z inz(z'2000-01-01-24.00.00.000000')
D time2 S Z inz(z'2000-01-02-00.00.00.000000')
D equal S N
D diff S 10I 0
/free
equal = (time1 = time2);
dsply equal;
diff = %diff(time1:time2:*MS);
dsply diff;
*inlr = *on;
/end-free

According to IBM they're not equal, but the difference in milliseconds is 0.

Joep Beckeringh

Mark Walter schreef:
Tested with this quick program
0001.00 Dtime1 S Z inz(z'2000-01-01-00.00.00.000000') 0002.00 Dtime2 S Z inz(z'2000-01-01-24.00.00.000000') 0003.00 Dequal S N 0004.00 /free 0005.00 equal = (time1 = time2); 0006.00 dsply equal; 0007.00 *inlr = *on; 0008.00 /end-free
result was

DSPLY 0

Not equal in the eyes of IBM.



Mark Walter
Paragon Consulting Services, Inc.
IBM Certified System i Specialist
717-764-7909 Ext. 26
mwalter@xxxxxxxxxxxxxxx
www.paragon-csi.com


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