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I believe Peter is somewhat correct...try splitting it. D int3 s 3i 0 int3 = %int(HSISN3) + 1; HSISN3 = %editc(int3 :'X'); Peter Levy <plevy@xxxxxxxxxx om> To Sent by: RPG programming on the AS400 / rpg400-l-bounces@ iSeries <rpg400-l@xxxxxxxxxxxx> midrange.com cc Subject 11/21/2006 10:33 Re: Using %editc() AM Please respond to RPG programming on the AS400 / iSeries <rpg400-l@midrang e.com> Just off the top of my head I'm guessing that the %INT() BIF outputs a binary integer that is probably a ten digit number. %EDITC() probably outputs a temporary value that is ten characters in length and when you EVAL it to a three character field it gets cut off. You could try using EVALR. Don Wereschuk wrote:
Hi All: I'm trying to use %editc() to add 1 to a 3 character field but it is not working quite right. I just can't see what I am doing wrong. The code is as follows: HSISN3 = %editc((%int(HSISN3) + 1):'X'); HSISN3 is defined as 3 character. The initial value is '001'. I was hoping after the calc that the value would be '002'. Instead I get '000'. The program is compiled as *ZONED. Can anyone help? TIA ****************************************** Don Wereschuk ISD - Programmer/Analyst Simcoe Parts Service Inc. Phone: 705-435-7814 Ex: 302 Fax: 705-435-6746 mailto:dwereschuk@xxxxxxxxxxxxxxx ****************************************** "Save the Cheerleader - Save the world" - Hiro Nakamura
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