RE: alarm() not working as expected

Oh, and here's my declaration of the errno() function:

     D errno           PR              *   ExtProc('__errno')

Note there are no parameters.

-Bob Cozzi
www.RPGxTools.com
RPG xTools - Enjoy programming again.


-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx]
On Behalf Of Lim Hock-Chai
Sent: Tuesday, January 17, 2006 10:29 AM
To: RPG programming on the AS400 / iSeries
Subject: alarm() not working as expected

I'm using alarm to control timeout on recv() and having the following
problem: 
 
1) When timeout occur (errno = EINTR), the program will continue to get
the timeout error without at least waiting for timeout to occur again
(which is set to 10 secs).  Below is a code snap shot.
 
 
C                ...loop start here
C                   eval      recvData = *blank                        
 *       set time out to 10 sec                                        
C                   callp     alarm(10)                                
C                   eval      recvlen = recv(hostSock :%addr(recvData) 
C                                           :%size(recvData)-10        
C                                           :0)                        
 *       disable timeout                                               
C                   callp     alarm(0)                                 
                                                                       
 *   if time out occured, return back to the main procedure to try to  
 *   send the @GO command.                                             
C                   if        (errno = EINTR)                          
C                   return    *off                                     
C                   endif          
C                    ....
C               ....end of loop                                    
 
Any help would be appreciated.