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I think the third parm in %subst is length not the to position. -----Original Message----- From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx]On Behalf Of rob@xxxxxxxxx Sent: Wednesday, August 17, 2005 8:14 AM To: rpg400-l@xxxxxxxxxxxx Subject: %subst bug? Have the following code in debug: 23 22 To=%scan(' ' : inlibl : From) - 1; 24 23 MbrLibrary=%subst(inlibl:from:To); 25 24 write InLiblOR; I break on the write line. From my monitor expressions window: MBRLIBRARY = BPCSUSR BP TO = 16 FROM = 10 INLIBL = BPCSUSRF BPCSUSR BPCSPTF BPCSF BPCSO Rob Berendt
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