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> What people didn't tell you (or at least I didn't see it mentioned) is > that you can use %dec() BIF to control the size of the intermediate > representation. Simply wrap your arithmetic expression in an additional > %dec() BIF and specify 10,0... this will cause the expression to use a > 10,0 intermediate... > > Of course, the resulting code is pretty ugly :) I've indented it to make > it a bit more obvious what I'm doing: > > > // original expression: > > parms.transNo = %editc( > (%dec(transNo: %size(transNo): 0) + 1) > : 'X'); > > // controlling intermediate results with %dec() > > parms.transNo = %editc( > %dec( > %dec(transNo: %size(transNo): 0) + 1 > : %size(parms.transNo): 0) > : 'X'); > > Thanks, this is what I was looking for. Robert
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