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> What people didn't tell you (or at least I didn't see it mentioned) is
> that you can use %dec() BIF to control the size of the intermediate
> representation.   Simply wrap your arithmetic expression in an additional
> %dec() BIF and specify 10,0... this will cause the expression to use a
> 10,0 intermediate...
> 
> Of course, the resulting code is pretty ugly :)  I've indented it to make
> it a bit more obvious what I'm doing:
> 
> 
>         // original expression:
> 
>           parms.transNo = %editc(
>                              (%dec(transNo: %size(transNo): 0) + 1)
>                           : 'X');
> 
>         // controlling intermediate results with %dec()
> 
>           parms.transNo = %editc(
>                               %dec(
>                                   %dec(transNo: %size(transNo): 0) + 1
>                               : %size(parms.transNo): 0)
>                           : 'X');
> 
> 


Thanks, this is what I was looking for.

Robert




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