RE: Binary Characters to Decimal

["Steve Richter" <srichter@xxxxxxxxxxxxx>]

Hi Bob,

what about itoa?  where the 3rd parm is the radix.  when radix = 2 the
output string contains a binary string.
  int nVlu ;
  char sResult[256] ;
  char* pResult ;
  nVlu = 25 ;
  pResult = itoa( nVlu, sResult, 2 ) ;

-Steve Richter


-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx
[mailto:rpg400-l-bounces@xxxxxxxxxxxx]On Behalf Of Bob cozzi
Sent: Monday, June 09, 2003 12:12 PM
To: 'RPG programming on the AS400 / iSeries'
Subject: RE: Binary Characters to Decimal


Jerry,
As Hans pointed out strtol (or strtoll for larger numbers) converts from
binary notation 101101 to decimal, but did you ever find a way to go
backwards? I have an old RPGIII grunt method technique that I've been using
for 10 years, but I'd rather find a simpler method. Just wondering.

Bob Cozzi
Cozzi Consulting
www.rpgiv.com


-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx]
On Behalf Of Hans Boldt
Sent: Friday, June 06, 2003 8:07 AM
To: rpg400-l@xxxxxxxxxxxx
Subject: Re: Binary Characters to Decimal

Feador, Jerry wrote:
> Hi All,
>
>       I've been tasked with converting a character representation of a
> binary number to it's decimal equivalent and vice versa. For example I
have
> a series of nine characters '001011101' and I'm suppose to get the AS/400
to
> come up with 93. Or I have the decimal number 321 and I need to get to
> '101000001'
>
>       I've checked the archives and all past information deals with the
> conversion of a true binary number to decimal, not this character
> representation of one....
>
>       Is it possible to just move this string into a binary field and then
> to a regular numeric field?

For conversion of numbers in base 2 to decimal, try the C run-time
library function "strtol()". Here's an example:

------------------------------------------------------------------
H dftactgrp(*no) bnddir('QC2LE')
D strtol          pr            10i 0 extproc('strtol')
D   nptr                          *   value options(*string)
D   endptr                        *   value
D   base                        10i 0 value
D ptr             s               *
  /free
     dsply (strtol('1': %addr(ptr): 2));
     dsply (strtol('10': %addr(ptr): 2));
     dsply (strtol('11': %addr(ptr): 2));
     dsply (strtol('100': %addr(ptr): 2));
     dsply (strtol('10010101': %addr(ptr): 2));
     *inlr = *on;
  /end-free
------------------------------------------------------------------

Cheers! Hans


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