Re: Convert hex to char (cvtch)

[Barbara Morris <bmorris@xxxxxxxxxx>]

Scott Klement wrote:
> 
> I think you wanted to use cvthc, rather than cvtch
> .
> I posted samples of calling these functions here:
> http://archive.midrange.com/rpg400-l/200205/msg00309.html
> 
> The problem, I believe is that it's trying to read 8 bytes starting
> at the beginning of your 'alp4HexBytes' variable.   Since that extends
> 4 bytes past the end of the parameter, it gives you the error that
> you can't access the memory at that offset.
> 

I prefer to use other names than cvthc and cvtch for the prototypes for
these functions.  I just cannot make it stick in my brain which is h and
which is c.  Unlike Bob, I don't think either meaning makes sense -
x'f0' and 'f0' both seem to fit h and c equally well.

Here are the prototypes I would use:
http://faq.midrange.com/data/cache/114.html

The offset error isn't quite as simple as going past the end of the
parameter.  There's almost always accessible storage there.  It's that
the following 4 bytes of storage doesn't have valid 2-byte hex values. 
I don't know why this causes an offset error, but I assume it's
something internal to the function that's getting invalidly offsetted.