RE: CPF7E56 - Identifier is ambiguous

["J Michael Smith" <Michael.Smith3@xxxxxxxx>]

Kim,

Have you had a response from Barbara on this question?

Michael 

-----Original Message-----
From: Ken Sims [mailto:mr2087@ke9nr.net]
Sent: Monday, January 20, 2003 8:45 PM
To: midrange-l@midrange.com; rpg400-l@midrange.com
Subject: Re: CPF7E56 - Identifier is ambiguous


Hi Matt -

>Why does the IBM debugger give this message for a non-qualified field
>(Identifier is ambiguous)?
>
>The field VITEMID is defined in three files.
>FVNDRCOST  IP   E           K DISK
>FVNDRMASTERIF   E           K DISK    PREFIX(VM)
>FVNDRITEM  IF   E           K DISK    PREFIX('VI.')
>
>Here's the definition for making one field qualified.
>D VI            E DS                  EXTNAME(VNDRITEM) QUALIFIED
>
>I try to view the contents of field VITEMID from VNDRCOST (not qualified nor
>prefixed).
>
>How do I tell the debugger to view this field without making modifications
>to the program to only prefix without the dot (.)?

Sorry for the delay.  I've been on vacation and even though I read the 
message, I wanted to try one thing out at work today before responding.

I'm sending this to the RPG400 list as well since it is specific to RPG IV 
debugging and since I would like some additional input from Barbara Morris.

Essentially the same question arose on the RPG400 list last week.

The answer is that if you are referencing a field with two instances, to 
see it in debug you must qualify it, even to reference a field in an 
unqualified data structure.  You do this with:

eval [field] of [datastructure]

According to Barbara, on V5R2 and following you can also do it with:

eval [datastructure].[field]

So far, so good.  The only thing I can't find a way to do, and this is 
where I would like some more input from Barbara ...

You can have a standalone field with the same name as a field in a 
qualified data structure.  You can view/change the data structure field 
using the methods given above.

Barbara, how can you view/change the standalone field?  There is no data 
structure name to associate it with.  Or is V5R2 smart enough to let you 
view/change the standalone field with just: eval [field]
V5R1 won't let you do this.

Ken
http://www.ke9nr.net/
Opinions expressed are my own and do not necessarily represent the views of 
my employer or anyone in their right mind.

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