RE: NOT on the left side

[Jim Langston <jlangston@xxxxxxxxxxx>]

Hmm.. can you just say:
PrettyField = (This = That);
Don't rightly know if that will work in RPG, it would work in C if
PrettyField was type bool (boolean). That is logically what you are asking
for.

That code will never work, because the compiler can't figure out what you
are trying to do (and I had to read your explanation before I figured it out
:) )

What that code is saying is (If PrettyField is *On to begin with):
If This=That;
   *On;
Else;
   *Off;
EndIf;

And that makes no sense, to me or the compiler :)

That the statement
PrettyField;
compiles is a total suprise to me.  But I doubt if it actually does anything
at all.

Regards,

Jim Langston

-----Original Message-----
From: rob@dekko.com [mailto:rob@dekko.com]

Suppose I have the following:
PrettyField is an indicator field - a type 'N'.
/free
 if This=That;
  PrettyField;
 else;
  Not PrettyField;
 Endif;
/end-free

The
  PrettyField;
compiles ok.  However the
  Not PrettyField;
does not.

Should I use the
PrettyField=*on;
PrettyField=*off;
logic, or should I hold my breath until I turn blue and hope IBM changes
this?

Rob Berendt