Re: Sanity check

["Peter Dow" <pcdow@xxxxxxxxx>]

Hi David,

Actually, if CM is not 'CM' and not 'DM', MEMO and PONO will not be
modified.  That is to say, the first time through (assuming this is the only
code that modifies MEMO and PONO), they would remain blank.  But if one pass
sets MEMO = '* CREDIT', and the next pass has CM not = 'CM' or 'DM', then
MEMO will still be '* CREDIT'.

hth,
Peter Dow
Dow Software Services, Inc.
909 425-0194 voice
909 425-0196 fax


----- Original Message -----
From: "David Schopp" <dschopp@imt.net>
Sent: Wednesday, January 09, 2002 12:36 PM
Subject: Sanity check


> Okay, I've got this section of code:
>
>
>             Factor1   OpCodFactor2   ResultLenDHHiLoEQ
> C                     CLEARMEMO
> C           CM        COMP 'CM'                     44 On if CM='CM'
> C  N44      CM        COMP 'DM'                     44 On if CM='DM'
> C   44      CM        IFEQ 'CM'
> C                     MOVEL'* CREDIT'MEMO    8
> C                     MOVE *BLANKS   PONO
> C                     ELSE
> C                     MOVE *BLANKS   PONO
> C                     MOVEL'*  DEBIT'MEMO    8
> C                     END
>
>
> Here's my question - My first thought was that this might be a coding
> error - that if CM was set to 'CM', Memo would contain '* CREDIT' and PONO
> would be blank, and if CM contained anything else, MEMO would contain '*
> DEBIT' and PONO would be blank.
>
> Then, I realized (I THINK) that the whole IFEQ stmt only is processed if
CM
> equals 'DM' or 'CM' - anything else and the IF stmt is bypassed, right?
So,
> if CM was blank, MEMO would be blank too, correct?



_________________________________________________________
Do You Yahoo!?
Get your free @yahoo.com address at http://mail.yahoo.com