Re: Passing pointers as parms

[jpcarr@xxxxxxxxxxxx]

Ah,   Well if you are doing a dynamic call to another program,   that is
what you are doing already.    If PgmA has a D/S (regardless of size) and
calls PgmB with the D/S as a parm,    You are already indeed passing a
pointer to PgmA's D/S already.   PgmB doesn't have the D/S,    it is just
mapping to the one in PgmA.

Try this example to prove my point;

Have a DS in a program(PGMA) (say 3000 bytes long)

Call a CLP program(PGMB) passing the D/S as a Parm

In the CLP program define the parm as 1 byte long,
Have the CLP program call a RPG program(PGMC)
passing the 1 byte parm,  have PGMC define the parm as a
3000 byte D/S and you will find that PGMC has indeed access to
all the stuff that PGMA put in it.     Cause,  you are only passing
a pointer  ( ie by Reference)


John Carr

-----------
Hi all,

I've a program which moves a buffer, (anywhere up to 32767), into a data
structure. The data appears correct in the subfields.

What I want to do is to call another program and instead of passing the
data/data structure, rather pass a pointer to the data and move the data
into a
data structure in the called program. Any suggestions, (yes, I'm busy
reading
the manual) ?

Regards
John.

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