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Okay, I changed my program to use UDate instead of *Date and it works
fine, thanks everyone.

But, as someone stated, UDate is the job date, not the system date.  Users
have been known to use // DATE mmddyy  (A S/36 emulation way to change
to job date) so I think the system date would be better.

I think I'll try this TIME, which I've never used, and Peter, I can call you 
Peter,
can't I?, are you saying that TIME gives the system time and not the job time?

Regards,

Jim Langston

phcoffin@us.ibm.com wrote:

> > So, without going into a whole rigamarole of createing a data structure,
> breaking it
> > down into MM DD CC YY and moving the parts, how do I initialize this
> field to
> > todays date?  And I should be creating it as Zones 6,0 right?
>
> DTODAY            S           L
>  * ...
> C                    TIME                TODAY
> C       *MDY         MOVE     TODAY      ParmAsOf
>
> I love date fields.
>
> Peter H. Coffin
> Database Application Management Tools Developer
> phcoffin@us.ibm.com
> T/L 665-6298 (Outside: 414-223-6298)
> http://w3.wwmkt.ibm.com/americasmi

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