|
I think this should take care of it:
delete from myfile a
where a.fldd || a.flde || rrn(a) <
(select max( b.fldd || b.flde || rrn(b) ) from myfile b
where a.flda = b.flda and a.fldb = b.fldb and a.fldc = b.fldc)
Vinay
On Wed, Nov 6, 2024 at 10:43 AM Vinay Gavankar <vinaygav@xxxxxxxxx> wrote:
If there are multiple records with the same flda thru flde values, they
will not be deleted.
I can live with that since I do not expect fldd and flde to be the same.
Of course if there any suggestions to overcome that, please let me know.
Vinay
On Wed, Nov 6, 2024 at 10:40 AM Vinay Gavankar <vinaygav@xxxxxxxxx> wrote:
I want to keep the instance where the fldd and flde are highest.
This seems to work (fldd and flde are varchar fields):
delete from myfile a
where a.fldd || a.flde <
(select max( b.fldd || b.flde ) from myfile b
where a.flda = b.flda and a.fldb = b.fldb and a.fldc = bfldc)
On Wed, Nov 6, 2024 at 10:36 AM Javier Sanchez <
javiersanchezbarquero@xxxxxxxxx> wrote:
Do you want to keep only one instance of the dupes? Or do you want to
sweep them all out?
JS
El mié, 6 nov 2024 a las 9:20, Vinay Gavankar (<vinaygav@xxxxxxxxx>)
escribió:
I tried the below :deleted. I
delete from myfile a
where rrn(a) >
(select min(rrn(b)) from myfile b
where a.flda = b.flda and a.fldb = b.fldb and a.fldc = b.fldc)
It kind of works, but I have no control over which records are
need to keep the record with highest value of fldd and flde (which arefrom
receipt date and time).
Any suggestions?
Vinay
On Wed, Nov 6, 2024 at 9:01 AM Vern Hamberg via MIDRANGE-L <
midrange-l@xxxxxxxxxxxxxxxxxx> wrote:
Allow me to expand on Darren's post - when he says "...an example
linkDB2..." I believe he means Db2 for Linux/Unix/Windows - Vinay, the
versionthat you give has 11.5 in it - that is the version for the LUW
https://www.ibm.com/support/pages/sql-reference-cross-platform-development-version-7of Db2 - it is not for IBM i.
The different versions or flavors of Db2 are very similar - IBM has a
website comparing them. Still, there are differences - here is a page
with links to resources -
You'reRegards
Vern
On 11/6/2024 7:21 AM, Darren Strong wrote:
I don't think you can delete from a virtual table like that.
IBMlooking at an example from DB2, but are probably running this on an
I,Google.
so its DB2 for I, which is different and maddeningly difficult to
Behalf OfThanks IBM.
-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> On
<midrange-l@lists.midrangecomVinay Gavankar
Sent: Tuesday, November 5, 2024 10:33 AM
To: Midrange Systems Technical Discussion
Do notSubject: Deleting duplicates from table
CAUTION: This email originated from outside of the organization.
knowclick links or open attachments unless you recognize the sender and
fldethe content is safe.(based
Hi,
I am trying to delete duplicate from a table, using following sql
on example from
https://www.ibm.com/docs/en/db2/11.5?topic=statements-delete )
delete from
(select rownumber() over (partition by flda, fldb, fldc
order by fldd desc,
mailingdesc) from myfile) as a(rn)
where rn > 1
I get an error over the first '(' before select:
Token ( was not valid. Valid tokens: <IDENTIFIER>.
What am I doing wrong?
TIA
Vinay
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