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I tried the below :
delete from myfile a
where rrn(a) >
(select min(rrn(b)) from myfile b
where a.flda = b.flda and a.fldb = b.fldb and a.fldc = b.fldc)

It kind of works, but I have no control over which records are deleted. I
need to keep the record with highest value of fldd and flde (which are
receipt date and time).

Any suggestions?
Vinay



On Wed, Nov 6, 2024 at 9:01 AM Vern Hamberg via MIDRANGE-L <
midrange-l@xxxxxxxxxxxxxxxxxx> wrote:

Allow me to expand on Darren's post - when he says "...an example from
DB2..." I believe he means Db2 for Linux/Unix/Windows - Vinay, the link
that you give has 11.5 in it - that is the version for the LUW version
of Db2 - it is not for IBM i.

The different versions or flavors of Db2 are very similar - IBM has a
website comparing them. Still, there are differences - here is a page
with links to resources -

https://www.ibm.com/support/pages/sql-reference-cross-platform-development-version-7

Regards
Vern

On 11/6/2024 7:21 AM, Darren Strong wrote:
I don't think you can delete from a virtual table like that. You're
looking at an example from DB2, but are probably running this on an IBM I,
so its DB2 for I, which is different and maddeningly difficult to Google.
Thanks IBM.


-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> On Behalf Of
Vinay Gavankar
Sent: Tuesday, November 5, 2024 10:33 AM
To: Midrange Systems Technical Discussion <midrange-l@lists.midrangecom>
Subject: Deleting duplicates from table

CAUTION: This email originated from outside of the organization. Do not
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Hi,

I am trying to delete duplicate from a table, using following sql (based
on example from
https://www.ibm.com/docs/en/db2/11.5?topic=statements-delete )

delete from
(select rownumber() over (partition by flda, fldb, fldc
order by fldd desc, flde
desc) from myfile) as a(rn)
where rn > 1

I get an error over the first '(' before select:
Token ( was not valid. Valid tokens: <IDENTIFIER>.

What am I doing wrong?

TIA
Vinay
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