Re: Scan and replace in CL variable -- MIDRANGE-L

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Seems to work:

pgm
dcl &logmsg *char 50 ('this has a quote ''<-here')
sndmsg &logmsg tousr(*requester)
rplstr (&LOGMSG) FROM('''') TO('')
sndmsg &logmsg tousr(*requester)
endpgm

when run produces this:
From . . . : LENNONS 03/03/22 18:35:24
this has a quote '<-here
From . . . : LENNONS 03/03/22 18:35:28
this has a quote <-here

You can find the code attached to this article (and probably ignore most of the article):
https://www.mcpressonline.com/programming-other/cl/techtip-entering-quotes-in-cl-variables-a-better-way

Any issues, let me know.

Sam

On 3/3/2022 12:52 PM, ~TA~ wrote:

I would be curious to know your results.

Thanks.

~TA~

On 3/3/2022 11:49 AM, Sam_L wrote:

In one of my exploring moments I created a RPLSTR command that given a CL variable would replace one string with another. I never did try it to replace something with nothing. But if you are interested, I'll try it later and report back.

Sam

On 3/3/2022 12:32 PM, ~TA~ wrote:

I need to remove apostrophes from a CL variable.

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