Ah yes, escape doesn't really help here, but maybe you don't need a LIKE at all, would this work?
declare global temporary table TABLE_1 as (
select * from(values('0110 EXFN 01 ABCD')) x(COL1)
) with data with replace
;;
declare global temporary table TABLE_2 as (
select * from(values('0110 EXFN 01'), ('____ EXFN 01')) x(COL1)
) with data with replace
;;
select *
from TABLE_1 T1
join TABLE_2 T2
on T2.COL1 = left(T1.COL1, length(T2.COL1))
Tim.
________________________________
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> on behalf of Justin Taylor <jtaylor.0ab@xxxxxxxxx>
Sent: 19 October 2021 19:18
To: MIDRANGE-L <midrange-l@xxxxxxxxxxxxxxxxxx>
Subject: Re: LIKE quandary
I got it now. I'd have to replace all % and _ in one column and then
specify the ESCAPE on the LIKE clause.
Unfortunately, the mailing list corrupted the example you copied from the
SQL reference. Let's see if I have better luck.
SELECT *
FROM TABLEY
WHERE C1 LIKE 'AAAA+%BBB%' ESCAPE '+'
Thanks
date: Tue, 19 Oct 2021 13:10:35 +0000
from: Tim Fathers <tim@xxxxxxxxxxxxx>
subject: Re: LIKE quandary
You could specify an escape character for the wildcard characters like
this:
SELECT *
FROM TABLEY
WHERE C1 LIKE ?AAAA+%BBB%? ESCAPE ?+?
Tim.
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