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if the count is immaterial...why include it?

select distinct type, code
from table

But the OP isn't looking for just the list of distinct type, codes...he
wants a list where the customers with those distinct combinations are
"somehow" included.

The "somehow" isn't very clear to me.

Charles


On Thu, Nov 19, 2020 at 8:17 AM Bob Czopek <bczopek@xxxxxxxxxxxxxxx> wrote:

Real life SQL Brain teaser (Dave)
Your question is how do I get distinct type and code permutations...

Select type, code, count(*)
From table
Group by type, code
Order by type, code;

The count is immaterial, you get all type distinct type, code
combinations...

----------------------------------------------------------------------

message: 1
date: Thu, 19 Nov 2020 14:30:24 +0100
from: Dave <dfx1@xxxxxxxxxxxxxx>
subject: Fwd: Real life SQL Brain teaser

Charles,

That?s amazing but it?s not quite there. If I select the lines where
rownbr = 1, I eliminate the list from customer 3, but I also lose the first
line from customer 2



cust type code ROWNBR

1 T1 C1 1

1 T3 C2 1



2 T1 C1 2

2 T2 C3 1

2 T3 C4 1



3 T1 C1 3

3 T2 C3 2

3 T3 C4 2



Thanks to everyone else for trying whose solution did not work !



End of MIDRANGE-L Digest, Vol 19, Issue 1670
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