Re: Real life SQL Brain teaser

-- get a numbered list of customers with each distinct (type,code)
with list as (select customer, type, code, row_number() over(partition by
type, code order by customer asc) as rowNbr
from mytbl)
select customer, type, code
from list
where rowNbr = 1
order by customer, type, code;

Charles

On Wed, Nov 18, 2020 at 11:07 AM Dave <dfx1@xxxxxxxxxxxxxx> wrote:

Hi,



Before I start writing a program, I was wondering if SQL could offer an
easier solution. I've been looking at using rank and over functions, but I
can't see it! :

In my table below there are 4 customers but only 3 distinct combinations of
Type and Code.

Customer Type Code

1 T1 C1

1 T1 C2

2 T2 C3

2 T2 C4

3 T5 C1

4 T1 C1

4 T1 C2



From this table, can I create the following table that contains each
combination of Type and Code only once ?

combination Type Code

1 T1 C1

1 T1 C2

2 T2 C3

2 T2 C4

3 T5 C1



TIA !
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