...ah, if using the colon format then the keyname must be a string, so single quotes, not double as in my example. Apologies.

________________________________
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> on behalf of Art Tostaine, Jr. <atostaine@xxxxxxxxx>
Sent: 07 January 2020 17:22
To: Midrange Systems Technical Discussion <midrange-l@xxxxxxxxxxxxxxxxxx>
Subject: Re: JSON Questions

Thank you Tim. The select doesn't like the colon after Deceasedds, I'm
trying to figure out the syntax.

On Tue, Jan 7, 2020 at 11:09 AM Tim Fathers <X700-IX2J@xxxxxxxxxxx> wrote:

I don't have access to a machine right now with SQL/JSON support so this
might not work as is, but I think you will need a JSON object inside and
outside the array and an array aggregate function, something like this:

select json_object(
"deceaseds":
json_arrayagg(
json_object(
"ExternalId": Nameid,
"Prefix": trim(PRFXDESC),
"FirstName": trim(firstname),
"MiddleName": trim(middlenme),
"LastName": trim(lastname),
"Suffix": trim(SUFFIXDES),
"BirthDate": trim(BIRTHDATE),
)
)
)
from namintprp

Tim.


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