that is wonderful. thanks!

On Mon, Nov 11, 2019 at 9:43 AM Birgitta Hauser <Hauser@xxxxxxxxxxxxxxx>

Try this:
select a.prodcode, sum(a.ordqty) totqty,
count (distinct c.ordnum) numOrders
from ordDetail a
group by a.prodcode
Mit freundlichen Grüßen / Best regards

Birgitta Hauser

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