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  2. MIDRANGE-L
  3. October 2018

Re: Using SQL, replace all characters less than x'40' in a string with blank

"MIDRANGE-L" <midrange-l-bounces@xxxxxxxxxxxx> wrote on 10/23/2018
10:50:37 AM:
"MIDRANGE-L" <midrange-l-bounces@xxxxxxxxxxxx> wrote on 10/23/2018
10:28:50 AM:
Currently, we have an RPG routine that does this via:

D FROM C x'000102030405060708090A0B0C0D0E0F+
D 101112131415161718191A1B1C1D1E1F+
D 202122232425262728292A2B2C2D2E2F+
D 303132333435363738393A3B3C3D3E3F'
D TO C ' -
D '
C EVAL NOTE = %XLATE(FROM:TO:NOTE)

Is there a way to do this in SQL that doesn't require 64 REPLACE
functions?


There should be a way to do that with the REGEX_REPLACE SQL
function.


Type. That would be REGEXP_REPLACE.


Sincerely,

Dave Clark

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