× The internal search function is temporarily non-functional. The current search engine is no longer viable and we are researching alternatives.
As a stop gap measure, we are using Google's custom search engine service.
If you know of an easy to use, open source, search engine ... please contact support@midrange.com.



Hi Vinay,
I have not made combinatorics since a long time... this is my suggestion
:
you need to multiply the number of values of each field to get the total
of combinations... this is your total number of records
from this number, if you subtract the current number of records in the
file... you should get the number of records to add...

using SQL this would become something like

select (
( (select distinct count(CONCAT(F1 , F2)) from FI)
* (select distinct count(CONCAT(F3 , F4)) from FI) )
- (select count(*) from FI) ) as X from sysibm/sysdummy1


cheers

Paul





From: Vinay Gavankar <vinaygav@xxxxxxxxx>
To: Midrange Systems Technical Discussion <midrange-l@xxxxxxxxxxxx>
Date: 18/07/2018 00:05
Subject: SEQUEL Help needed
Sent by: "MIDRANGE-L" <midrange-l-bounces@xxxxxxxxxxxx>



I was looking for some help to create an SEQUEL to find out how many
records would get added when I run a program.

I am not sure how to best formulate my problem, but let me try:

I have one large file (180 million recs) with fields F1, F2, F3, F4

It is defined as Unique on fields F2, F3, F4

I will be writing a program to create additional records in file if for a
particular value of F1, there exist more than one value of F2 and each
combination of F1/F2 does not have same F3/F4 combination.

I want to know how many additional records will be created by the
program.

I think it is best explained by examples of data in the records in file:

Assume field F1 has values An, F2 has Bn, F3 has Cn and F4 has Dn

Example1:
A1, B1, C1, D1
No new records will be created for A1

Example2:
A2, B2, C2, D2
A2, B2, C3, D3
A2, B3, C2, D2
A2, B3, C3, D3
No new records will be created for A2

Example 3:
A3, B4, C4, D4
A3, B4, C5, D5
A3, B5, C6, D6
Following new records will be created for A3
A3, B4, C6, D6
A3, B5, C4, D4
A3, B5, C5, D5

Example 4:
A4, B6, C7, D7
A4, B6, C8, D8
A4, B7, C7, D7
Following new records will be created for A4
A4, B7, C8, D8

I hope I haven't made a typo and made myself clear.

Even though it MAY be possible to insert these records thru SEQUEL, it
won;t be allowed in production environment, so I will have to write a
program.

I am just trying to figure up-front out how many records will be added by
the program.

Thanks in advance.

Vinay

As an Amazon Associate we earn from qualifying purchases.

This thread ...

Follow-Ups:
Replies:

Follow On AppleNews
Return to Archive home page | Return to MIDRANGE.COM home page

This mailing list archive is Copyright 1997-2024 by midrange.com and David Gibbs as a compilation work. Use of the archive is restricted to research of a business or technical nature. Any other uses are prohibited. Full details are available on our policy page. If you have questions about this, please contact [javascript protected email address].

Operating expenses for this site are earned using the Amazon Associate program and Google Adsense.