I've seen the -7008 error when the system wants a table to be journaled,
that is involved in an UPDATE or DELETE, with foreign keys present, and the
table is not journaled.

Try starting journaling on the two tables using the STRJRNPF command, and
then perform the UPDATE on the child table.

If I recall correctly, the system will issue -7008 even when the primary or
foreign key values are not changing. I think the journals are used to
ensure that orphan foreign keys are not created, and the mechanisms aren't
as sophisticated as one might anticipate.

Mike


message: 3
date: Fri, 23 Oct 2015 16:47:11 +0000
from: Justin Dearing <zippy1981@xxxxxxxxx>
subject: Foreign key causing Error:55019 Message:SQLSTATE=55019
SQLCODE=-7008

I would think a simple foreign key would be simple. Its not apparently.

tl;dr: If I add a foriegn key to a child table, I can insert into the
parent table, but not update it (I'm not updating the foreign key column)

The long version

I have two tables ABBAPF and ABBACPF. They don't have journals created
according to the output of the create table statement. In the later I have
a foreign key setup like this:

AD_ID FOR COLUMN ABADROWID BIGINT NOT NULL
CONSTRAINT WEBLIB.FK_ABBACPF_ABBAPF REFERENCES WEBLIB.ABBAPF(ROWID),

I can insert into the parent table with no problem. However, this update
fails


UPDATE WEBLIB.ABBAPF SET XML_COL = XMLPARSE(DOCUMENT '<xmlRoot/>'),
ABMSGSTAMP = CURRENT TIMESTAMP, STATUS = 0, MESSAGE = 'Success' WHERE ROWID
= 1 WITH NC

[SQL7008] ABBAPF in WEBLIB not valid for operation. [SQL State=55019, DB
Errorcode=-7008]

Note I tried adding the WITH NC after the fact. removing it doesn't help.

Dropping the child table makes the update work. therefore I'm pretty sure
its not journaling like this article says

http://www-01.ibm.com/support/docview.wss?uid=swg21380662


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