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My point is that it isn't "spinning through the disk". Probably never touches disk at all. The index is most likely entirely contained in a memory page or two. That index is maintained within memory as a set of vectors in trees. The system need only make a few thunks through the vector map within memory to see that there is no index that matches your key.

-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx [mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of RPGLIST
Sent: Wednesday, January 23, 2013 10:41 AM
To: Midrange Systems Technical Discussion
Subject: RE: I/O count differences

I undestand that, I guess what I'm trying to determine how to evaluate the fact that its still taking resources and time (as minute as it may be) to spin through the disk.


The system uses the index only on a no-hit. Never touches the data at all.

-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of RPGLIST
Sent: Wednesday, January 23, 2013 10:23 AM
To: midrange-l@xxxxxxxxxxxx
Subject: I/O count differences

I need an explanation on this if someone would be so kind.

When I chain to a file with a key and get a hit, I fully expect the
I/O count to increase by 1, even though it is sort of doing a SETLL
and then a READE within the chain process. However, whenever it
doesn't find a record it shows no I/O count.

I understand that since it didn't find a record it brough nothing back
from the disk and therefore didn't increase the I/O count, but it
certainly used resources to spin all the way through that drive
disk....Is there anywhere that the system accoutns for this in the statistics?

I see the same results when performing a SETLL, If %Equal, actually
even if there is a hit I don't see an I/O count until the READE statement.



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