In pseudo code
With clientolder as
(select a.clientnbr from table a where
a.child_bday01 < (current-date - 20years) or
a.child_bday02 < (current-date - 20years) or
...
a.child_bdayn < (current-date - 20years)),
clientyounger as
(select b.clientnbr from table b where
b.child_bday01 > (current-date - 20years) or
b.child_bday02 > (current-date - 20years) or
...
b.child_bdayn > (current-date - 20years))
select z.clientnbr from clientolder z join clientyounger x on
z.clientnbr = x.clientnbr
at a quick guess
Alan Shore
Programmer/Analyst, Direct Response
E:AShore@xxxxxxxx
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C:(631) 880-8640
"If you're going through Hell, keep going" - Winston Churchill
-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx [mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Dave
Sent: Monday, April 02, 2012 11:56 AM
To: Midrange Systems Technical Discussion
Subject: Sql muddle
Hi,
I'm getting in a real twist with this one :
Given a table with a client and his children with their dates of birth, I want to select those clients having at least one child aged over 20 AND at least one child under 20.
The answer would be very much appreciated.
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