RE: Full outer join to show differences

-----Message d'origine-----
De : midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] De la part de Birgitta Hauser
Envoyé : jeudi 10 mars 2011 15:20
À : 'Midrange Systems Technical Discussion'
Objet : AW: Full outer join to show differences

Hi,

you only want to see the rows that are either different or do
not exist?

IMHO joining is the wrong way, what you need is merging.

The following statement returns all rows that are not identical:

( Select * from Table1
Except
Select * from Table2)
Union
( Select * from Table2
Except
Select * from Table1)


Mit freundlichen Grüßen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the
stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek
Bok) "What is worse than training your staff and losing them?
Not training them and keeping them!"


-----Ursprüngliche Nachricht-----
Von: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] Im Auftrag von David FOXWELL
Gesendet: Thursday, 10. March 2011 14:39
An: Midrange Systems Technical Discussion
Betreff: Full outer join to show differences

Hi,

I'm comparing 2 tables after a test with a full outer join ie

select * from before b full outer join after a on b.id=a.id

But I only want to see the data that's different in the after
table or not there at all, ie null in that select.

So I add
where a.data<>b.data

This now excludes the missing after lines.

So I need something like

select * from before b full outer join after a on b.id=a.id
where a.data<>b.data or b.data= null

How do I get those null rows?

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