AW: Full outer join to show differences

["Birgitta Hauser" <Hauser@xxxxxxxxxxxxxxx>]

Hi,

you only want to see the rows that are either different or do not exist?

IMHO joining is the wrong way, what you need is merging.

The following statement returns all rows that are not identical:

    (    Select * from Table1
     Except
         Select * from Table2)
Union
    (    Select * from Table2
     Except
         Select * from Table1)


Mit freundlichen Grüßen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them
and keeping them!"


-----Ursprüngliche Nachricht-----
Von: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] Im Auftrag von David FOXWELL
Gesendet: Thursday, 10. March 2011 14:39
An: Midrange Systems Technical Discussion
Betreff: Full outer join to show differences 

Hi,
 
I'm comparing 2 tables after a test with a full outer join ie 
 
select * from before b full outer join after  a on b.id=a.id
 
But I only want to see the data that's different in the after table or not
there at all, ie null in that select.
 
So I add
where a.data<>b.data 
 
This now excludes the missing after lines. 
 
So I need something like 
 
select * from before b full outer join after  a on b.id=a.id
where a.data<>b.data  or 
b.data= null

How do I get those null rows?