Rank may give you what you want.
Select column1, column2, rank() over(partition by column2 order by column2), column3 from table.
You may need to change the over portion this to get it to work for you.
-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx [mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Pete Helgren
Sent: Monday, March 07, 2011 3:41 PM
To: Midrange Systems Technical Discussion
Subject: Counting Occurrences with SQL
I am have a data set that looks like the following:
BB8179 04/17/11 04/02/11
BE7214 04/17/11 04/02/11
BD9607 04/17/11 04/02/11
BB6382 04/17/11 04/02/11
BB7942 04/17/11 04/02/11
BE7487 04/17/11 04/02/11
BE7488 04/18/11 04/02/11
BE2178 04/18/11 04/02/11
BE1618 04/18/11 04/02/11
BE7489 04/18/11 04/02/11
BE2179 04/18/11 04/02/11
BD9608 04/21/11 04/02/11
BE2180 04/21/11 04/02/11
BE8955 04/21/11 04/02/11
BE1696 04/21/11 04/02/11
What I would like to do is count the unique occurrences of the first
date column. Something like:
BB8179 04/17/11 1 04/02/11
BE7214 04/17/11 1 04/02/11
BD9607 04/17/11 1 04/02/11
BB6382 04/17/11 1 04/02/11
BB7942 04/17/11 1 04/02/11
BE7487 04/17/11 1 04/02/11
BE7488 04/18/11 2 04/02/11
BE2178 04/18/11 2 04/02/11
BE1618 04/18/11 2 04/02/11
BE7489 04/18/11 2 04/02/11
BE2179 04/18/11 2 04/02/11
BD9608 04/21/11 3 04/02/11
BE2180 04/21/11 3 04/02/11
BE8955 04/21/11 3 04/02/11
BE1696 04/21/11 3 04/02/11
Actually there are more columns involved here but this data set
illustrates the challenge. Can't seem to wrap my head around the whole
thing but I may need a subselect to get the count of the occurrences...
Thanks
--
Pete Helgren
Value Added Software, Inc
www.asaap.com
www.opensource4i.com
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