Re: Counting Occurrences with SQL

Maybe something like:

WITH T1 as (SELECT IDENT, DATE1, COUNT(*) as TIMES
FROM MYTABLE
GROUP BY IDENT, DATE1)
SELECT a.IDENT, a.DATE1, TIMES, DATE2
FROM MYTABLE A
JOIN T1 on a.IDENT = T1.IDENT
and a.DATE1 = T1.DATE1

"Pete Helgren" <pete@xxxxxxxxxx> wrote:

I am have a data set that looks like the following:

BB8179 04/17/11 04/02/11
BE7214 04/17/11 04/02/11
BD9607 04/17/11 04/02/11
BB6382 04/17/11 04/02/11
BB7942 04/17/11 04/02/11
BE7487 04/17/11 04/02/11
BE7488 04/18/11 04/02/11
BE2178 04/18/11 04/02/11
BE1618 04/18/11 04/02/11
BE7489 04/18/11 04/02/11
BE2179 04/18/11 04/02/11
BD9608 04/21/11 04/02/11
BE2180 04/21/11 04/02/11
BE8955 04/21/11 04/02/11
BE1696 04/21/11 04/02/11

What I would like to do is count the unique occurrences of the first
date column. Something like:

BB8179 04/17/11 1 04/02/11
BE7214 04/17/11 1 04/02/11
BD9607 04/17/11 1 04/02/11
BB6382 04/17/11 1 04/02/11
BB7942 04/17/11 1 04/02/11
BE7487 04/17/11 1 04/02/11
BE7488 04/18/11 2 04/02/11
BE2178 04/18/11 2 04/02/11
BE1618 04/18/11 2 04/02/11
BE7489 04/18/11 2 04/02/11
BE2179 04/18/11 2 04/02/11
BD9608 04/21/11 3 04/02/11
BE2180 04/21/11 3 04/02/11
BE8955 04/21/11 3 04/02/11
BE1696 04/21/11 3 04/02/11

Actually there are more columns involved here but this data set
illustrates the challenge. Can't seem to wrap my head around the whole

thing but I may need a subselect to get the count of the occurrences...

Thanks

--
Pete Helgren
Value Added Software, Inc
www.asaap.com
www.opensource4i.com

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