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Bruce, the only reason I had plbptp in my select is because I was trying
to figure out why I am getting the multiple records. I have removed it
but I'm still getting the same result.
-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of R Bruce Hoffman
Sent: Wednesday, September 09, 2009 8:21 AM
To: Midrange Systems Technical Discussion
Subject: Re: Help with SQL statement
If you don't want plbptp in your output, why is included in output and
grouped? It doesn't have to be in the result set just because it's a
predicate.
Smith, Mike wrote:
I have the following SQL statement.and
SELECT eeun, eedpt, plbemp, eenam, plbbg1, sum(plbhrs), plbptp FROM
PRLBH, EEMP
WHERE PLBEMP = EEENO and PLBPTP in('CO','OH', '6D','7D','OG') and
EETDT = 0 and
EEDPT in (select PRDPT from PROVRDPT00 where PRNAME = 'BRANDTNS')
PLBEDT
= 20090731
GROUP BY PLBEMP,EENAM ,EEDPT, EEUN, PLBBG1 ,plbptp
ORDER BY EEDPT,PLBEMP
That produces results like this
Eedpt plbemp eenam
plbbg1 eeun sum(plbhrs) PLBPTP
091 165 SMITH MICHAEL A 091
Y 16.00 470.00 OH
091 165 SMITH MICHAEL A 091
Y 5.50 470.00 6D
091 165 SMITH MICHAEL A 091
Y 16.00 470.00 6C
I get 3 records because there are three different values of PLBPTP
I can't get my grouping to work so that I get 1 record that looks like
thisconfidential and privileged communication. If you have received this
091 165 SMITH, MICHAEL A 091 Y
37.50 470.00
Can you suggest a way to make this work?
Thanks
Mike
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R Bruce Hoffman
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