Re: SQL find hexadecimal values in a given range

David
MC Press online have published 2 articles in the past
Non-translateable characters
Non-display characters
At the time they were first published, I marked them in my favorites, but
since that time MC press online has been revamped, and they no longer work
I tried to search their archives, but found nothing, but that might be my
fault.
Maybe someone else can locate the present address of these articles for you
to use.



Alan Shore
Programmer/Analyst, Distribution
E:AShore@xxxxxxxxxxx
P:(631) 200-5019
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"If you're going through Hell, keep going" - Winston Churchill

midrange-l-bounces@xxxxxxxxxxxx wrote on 03/26/2009 12:28:25 PM:

David

I really don't think SQL is the tool for this - if this is about
replacing non-displayable characters. You would be better off using the
%xlate function, I think. It is useful for simple case conversion, but
you could set up 2 constants - the first would be something like

x'000102030405060708090A0B0C0D0E0F101112131415161718191A1B1C1D1E1F202122232425262728292A2B2C2D2E2F303132333435363738393A3B3C3D3E3FFF'

and the other would be all blanks and the same length - remember that
the above value is in HEX, so it is 2 hex digits for each "character" or
byte - you need the same number of blanks as there are bytes above. Then
use %xlate - I don't have the exact syntax right in my head - get the
ILE RPG manual. %xlate will do the read through the entire string and do
the replace for you.

I do hope there is an easier way!!

HTH
Vern

David FOXWELL wrote:

This will show the first position and all rows containing the value

hex 40.

SELECT locate( X'40', myfield, 1), myfield FROM myfile WHERE
locate( X'40', myfield)>0

How can I find hex values less that 40?

Thanks

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