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David
I really don't think SQL is the tool for this - if this is about
replacing non-displayable characters. You would be better off using the
%xlate function, I think. It is useful for simple case conversion, but
you could set up 2 constants - the first would be something like
x'000102030405060708090A0B0C0D0E0F101112131415161718191A1B1C1D1E1F202122232425262728292A2B2C2D2E2F303132333435363738393A3B3C3D3E3FFF'
and the other would be all blanks and the same length - remember that
the above value is in HEX, so it is 2 hex digits for each "character" or
byte - you need the same number of blanks as there are bytes above. Then
use %xlate - I don't have the exact syntax right in my head - get the
ILE RPG manual. %xlate will do the read through the entire string and do
the replace for you.
I do hope there is an easier way!!
HTH
Vern
David FOXWELL wrote:
This will show the first position and all rows containing the value hex 40.
SELECT locate( X'40', myfield, 1), myfield FROM myfile WHERE
locate( X'40', myfield)>0
How can I find hex values less that 40?
Thanks
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