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Actually Rob, I take that back...

Re-reading the OP, it seems 1-10 is what he's interested in.

But then he talks about finding the missing numbers in a given range....

In that case, depending on the size of the range, you're solution might work (but it's 6.1 only
right?). Or a modified version of Michael's....

Exec sql
Select min(a.field+1) from file a
where not exists(select '1' from file b where a.field+1 = b.field)
and a.field between :rangeStart and :rangeEnd

Note you'd still need something extra in case the starting value, ie 1 was missing.

Charles Wilt
Software Engineer
CINTAS Corporation - IT 92B

513.701.1307

wiltc@xxxxxxxxxx


-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx [mailto:midrange-l-
bounces@xxxxxxxxxxxx] On Behalf Of Wilt, Charles
Sent: Wednesday, April 16, 2008 9:08 AM
To: Midrange Systems Technical Discussion
Subject: RE:

I doubt that the OP is really only concerned with 1-10. Headk you could
check that manually in the
time it's taken to read the reply's to the list.

So I think Michael's solution is a good one.

You could make it check for 1...but may not be worth the effort.


With an SQL index over field, you should get decent performance with
"index only access" even though
the entire index would be scanned.



Charles Wilt
Software Engineer
CINTAS Corporation - IT 92B
513.701.1307

wiltc@xxxxxxxxxx


-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx [mailto:midrange-l-
bounces@xxxxxxxxxxxx] On Behalf Of rob@xxxxxxxxx
Sent: Wednesday, April 16, 2008 8:55 AM
To: Midrange Systems Technical Discussion
Subject: Re:

This works on V6R1

with list(counter) as
(values(1),(2),(3),(4),(5),(6),(7),(8),(9),(10))
select counter from list
where counter not in(select thekey from qtemp/foxwell)

So if qtemp/foxwell contains 2, 3 and 5 you will get back: 1, 4, 6, 7,
8,
9, 10


Rob Berendt
--
Group Dekko Services, LLC
Dept 01.073
Dock 108
6928N 400E
Kendallville, IN 46755
http://www.dekko.com

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