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FWiW to get one winner of 10M requires only seventy balls, seven sets
of ten balls numbered zero to nine, spread across seven bins. The
problem is when there are for example 9499990 entrants. That is, if the
first bin selects ball-9, then the second bin must have ball-5 to ball-9
removed, to allow the game to continue. Similarly if the first six
numbers selected are 949999, then the seventh tube must have balls one
to nine removed, which means no seventh number need be selected; the
outcome is already known. Does that invalidate the game since it is no
longer seven distinct "Ten Choose One" [IIRC what they are called] problems?
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