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Sweet! That's what I wanted...thanks Vern!

On 8/17/07, Vernon Hamberg <vhamberg@xxxxxxxxxxx> wrote:
Michael

Based on another recent post, here's a way to get what you want--

select strip(translate(char20,' ', ':')), count(*)
from mryan
group by strip(translate(char20,' ', ':'))

If you had more punctuations, just add them to the 3rd parameter of
translate().

HTH
Vern

At 08:18 AM 8/17/2007, you wrote:

Anyone know how to do this? I have data that looks like this:

Rattan
Traditional
:Rattan:
Contemporary

I'd like to produce a list like

Rattan 2
Traditional 1
Contemporary 1

The 'extra' search result with the colons around it should be the same
as the search result without the colons.

Thanks...
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