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OOhhh - nice one Michael.


Alan Shore

NBTY, Inc
(631) 244-2000 ext. 5019
AShore@xxxxxxxx
"If you're going through Hell, keep going" - Winston Churchill

midrange-l-bounces@xxxxxxxxxxxx wrote on 08/17/2007 09:41:03 AM:

Michael

Based on another recent post, here's a way to get what you want--

select strip(translate(char20,' ', ':')), count(*)
from mryan
group by strip(translate(char20,' ', ':'))

If you had more punctuations, just add them to the 3rd parameter of
translate().

HTH
Vern

At 08:18 AM 8/17/2007, you wrote:

Anyone know how to do this? I have data that looks like this:

Rattan
Traditional
:Rattan:
Contemporary

I'd like to produce a list like

Rattan 2
Traditional 1
Contemporary 1

The 'extra' search result with the colons around it should be the same
as the search result without the colons.

Thanks...
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