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Michaellist
Based on another recent post, here's a way to get what you want--
select strip(translate(char20,' ', ':')), count(*)
from mryan
group by strip(translate(char20,' ', ':'))
If you had more punctuations, just add them to the 3rd parameter of
translate().
HTH
Vern
At 08:18 AM 8/17/2007, you wrote:
Anyone know how to do this? I have data that looks like this:
Rattan
Traditional
:Rattan:
Contemporary
I'd like to produce a list like
Rattan 2
Traditional 1
Contemporary 1
The 'extra' search result with the colons around it should be the same
as the search result without the colons.
Thanks...
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