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Just enter

SELECT count(*) FROM jrnfile WHERE joentt = 'LD'



-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of fbocch2595@xxxxxxx
Sent: Tuesday, February 06, 2007 2:49 PM
To: midrange-l@xxxxxxxxxxxx
Subject: Re: SQL Question

Yes, I wanted a value of the # of jojob's where joentt is LD.  
 
 
 
-----Original Message-----
From: mrosinger@xxxxxxxxx
To: midrange-l@xxxxxxxxxxxx
Sent: Tue, 6 Feb 2007 3:05 PM
Subject: Re: SQL Question


Frank,

Did you mean for each unique value of JOJOB you want a count of that
grouping? If so, Don's response is correct. I understood from your
posting that you wanted a total where joentt is "LD".

--
Regards,

Michael Rosinger
Systems Programmer / DBA
Computer Credit, Inc.
640 West Fourth Street
Winston-Salem, NC  27101
336-761-1524
m rosinger at cciws dot com
"Don Tully Sr" <donald.tully@xxxxxxx> wrote in message
news:mailman.2364.1170791734.2713.midrange-l@xxxxxxxxxxxxxxx
Select JOjob, count(*) from jrnfile where joentt='LD'
group by Jojob

Don

-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of 
fbocch2595@xxxxxxx
Sent: Tuesday, February 06, 2007 1:40 PM
To: midrange-l@xxxxxxxxxxxx
Subject: Re: SQL Question

Hi folks, here's my statement;

SELECT * FROM jrnfile WHERE joentt = 'LD' ORDER BY JOJOB

I'm looking to get a total of the jojob entries that have joentt of
LD. 
How
is that done?

Thanks, Frank



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