RE: IBM Unleashes World's Most Powerful Server

Darrell,

The understood unit of measure is simply the acquisition cost /
transaction per minute.

System Information
Total System Cost       11,967,178 US $  
TPC-C Throughput                4,016,222 
Price/Performance       2.98 US $  

$11,967,178 / 4,016,222 = $2.98 

I suppose it would be possible for a benchmark to figure actual
operating costs per transaction.  But I doubt it would happen anytime
soon.  Imagine trying to standardize all the variables that go into
operating costs.  Although, it might be interesting to have a
pseudo-operating cost per transaction calculation that included
maintenance costs and electrical usage at full load.

HTH,


Charles Wilt
--
iSeries Systems Administrator / Developer
Mitsubishi Electric Automotive America
ph: 513-573-4343
fax: 513-398-1121
  

-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx 
[mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Darrell A Martin
Sent: Tuesday, July 25, 2006 11:02 AM
To: Midrange Systems Technical Discussion
Subject: RE: IBM Unleashes World's Most Powerful Server

Don:

Sure, the issue has to be units of measure. What was written 
is obvious 
and clear, and just as clearly and obviously wrong -- unless 
there is an 
"understood" standard measurement. There may be. I wouldn't 
be surprised. 
But, I don't know what it is.

Darrell

Darrell A. Martin  -  754-2187
Manager, Computer Operations
dmartin@xxxxxxxxxxxxx

"Fisher, Don" <dfisher@xxxxxxxxxxxxx> wrote on 07/25/2006 09:49:42 AM:

I could be wrong, but the price-performance calculation is not 
operating cost, but acquisition cost.  I believe the article was 
saying the p5-595 will cost $2.98 per transaction to acquire.  In 
the context of the article, that would be the 4,016,222 transactions
per minute multiplied by $2.98.

Donald R. Fisher, III
Project Manager
RoomStore, Inc.

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