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Change the session attribute to create a file. Execute: SELECT keyField FROM filename WHERE keyField <> 0 GROUP BY keyField HAVING count(*) > 1 Execute(appropriate SQL function) based on the result file: UPDATE filea set keyField = 0 WHERE keyfield in (SELECT keyField from resultFile) Previously to using this method, I tried the subselect from within the UPDATE and it took forwever. Michael -----Original Message----- From: Mark Allen [mailto:mallen@xxxxxxxx] Sent: Friday, May 09, 2003 12:16 PM To: midrange-l@xxxxxxxxxxxx Subject: Best Way to find duplicate records in same file I need to add duplicate record checking in a file we received from a switch. (I'll just add it to the CL that already FIXES a bunch of stuff in the file anyways) and was wondering what the best (i.e easy/fast) to do it would be. I've come up with: 1. Run a query against the file, sorted by entire record, level break on entire record, count. Output Query results to file and then do cpyf. 2. Build a file keyed on all 210 bytes, read original chain to new file, if not found write it 3. SQL ??? not done much with it but maybe it could do? Mark Allen IS Manager Wilkes Telephone & Electric 11 W. Court Street Washington, GA 30673 Phone: (706) 678-9565 Fax: (706) 678-1000 _______________________________________________ This is the Midrange Systems Technical Discussion (MIDRANGE-L) mailing list To post a message email: MIDRANGE-L@xxxxxxxxxxxx To subscribe, unsubscribe, or change list options, visit: http://lists.midrange.com/mailman/listinfo.cgi/midrange-l or email: MIDRANGE-L-request@xxxxxxxxxxxx Before posting, please take a moment to review the archives at http://archive.midrange.com/midrange-l.
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