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First thought requres common table expressions which I don't think exist until V5R1, but if you're >=V5R1 then: with z as (select field1 from tim group by field1 having count(*) > 1) select count(*) from z -Walden ------------ Walden H Leverich III President Tech Software (516) 627-3800 x11 (208) 692-3308 eFax WaldenL@TechSoftInc.com http://www.TechSoftInc.com Quiquid latine dictum sit altum viditur. (Whatever is said in Latin seems profound.) -----Original Message----- From: Hatzenbeler, Tim [mailto:thatzenbeler@clinitech.net] Sent: Thursday, May 09, 2002 18:18 To: 'midrange-l@midrange.com' Subject: New: SQL (Count/Duplicate) Question This message is in MIME format. Since your mail reader does not understand this format, some or all of this message may not be legible. -- [ Picked text/plain from multipart/alternative ] I have a table, that sometimes has duplicate values... And I would like to create an SQL, that will return back to me a count(*) of the number of duplicates it found, so if my table has this in it... Table = Tim field1 -------- 1 2 3 3 4 4 4 5 it would return back a count of *2* because there were 2 distinct groups that had duplicates group (3 and 4). Is that easily done? Thanks, tim This e-mail message, including any attachments, is for the sole use of the intended recipient(s) and may contain confidential or privileged information. Any unauthorized review; use, disclosure or distribution is prohibited. If you are not the intended recipient, please contact the sender by reply e-mail and destroy the message. _______________________________________________ This is the Midrange Systems Technical Discussion (MIDRANGE-L) mailing list To post a message email: MIDRANGE-L@midrange.com To subscribe, unsubscribe, or change list options, visit: http://lists.midrange.com/cgi-bin/listinfo/midrange-l or email: MIDRANGE-L-request@midrange.com Before posting, please take a moment to review the archives at http://archive.midrange.com/midrange-l.
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