RE: SQL (Count/Duplicate) Question

First thought requres common table expressions which I don't think exist
until V5R1, but if you're >=V5R1 then:

with z as (select field1 from tim group by field1 having count(*) > 1)
select count(*) from z

-Walden

------------
Walden H Leverich III
President
Tech Software
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Quiquid latine dictum sit altum viditur.
(Whatever is said in Latin seems profound.)



-----Original Message-----
From: Hatzenbeler, Tim [mailto:thatzenbeler@clinitech.net]
Sent: Thursday, May 09, 2002 18:18
To: 'midrange-l@midrange.com'
Subject: New: SQL (Count/Duplicate) Question


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I have a table, that sometimes has duplicate values...  And I would like to
create an SQL, that will return back to me a count(*) of the number of
duplicates it found, so if my table has this in it...

Table = Tim
field1
--------
1
2
3
3
4
4
4
5

it would return back a count of  *2*  because there were 2 distinct groups
that had duplicates   group (3 and 4).

Is that easily done?

Thanks, tim


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