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Tim,

Give this a try.

SELECT count(*)
  FROM (SELECT field1, count(*)
             FROM tim
             GROUP BY field1
             HAVING count(*) > 1)

Regards,
Stan


-----Original Message-----
From: Hatzenbeler, Tim [mailto:thatzenbeler@clinitech.net]
Sent: Thursday, 09 May, 2002 3:18 PM
To: 'midrange-l@midrange.com'
Subject: New: SQL (Count/Duplicate) Question


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I have a table, that sometimes has duplicate values...  And I would like to
create an SQL, that will return back to me a count(*) of the number of
duplicates it found, so if my table has this in it...

Table = Tim
field1
--------
1
2
3
3
4
4
4
5

it would return back a count of  *2*  because there were 2 distinct groups
that had duplicates   group (3 and 4).

Is that easily done?

Thanks, tim


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