|
I believe the problem is the "e-" and "R-". They should probably be "e--"
and "R--", and someone's e-mail editor somewhere decided it'd be helpful,
and convert "--" into a longer dash... (I know Word would do that) and
then when it got converted back to plain text, it was just one...
The following code compiles:
#include <stdio.h>
void P(const char *);
main () {
int *u, k, R, e, C;
for(;P("\n"),R--;P("|"))for(e=C;e--;P("_"+(*u++/8)%2))P("|"+(*u/4)%2);
}
void P(const char *huh) {
printf("%s", huh);
}
It certainly doesn't do anything useful, though... and it crashes pretty
quick, since adding to the pointer returned by "_" and "|" is a REALLY bad
idea...
Oh well... I was hoping the code would do something cool like print a
message or something. sigh.
On Thu, 7 Feb 2002 MacWheel99@aol.com wrote:
> But what version were you running it on? ... perhaps the syntax has changed.
> Could there be a typo in the transcription?
>
> > Okay, so I decided to try it:
> >
> > I cut/pasted "for(;P("\n"),
> R-;P("|"))for(e=C;e-;P("_"+(*u++/8)%2))P("|"+(*u/
> > 4)%2)"
> > into a file called "hoax.c".
> >
> > Tried to compile it:
> >
> > (w7) 4:13pm ~ > cc -o hoax hoax.c
> > hoax.c:1: syntax error before `for'
> >
> > Eh? It doesn't even get as far as the first word in the statement before
> > failing.
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