Alan,

Which solution of Alexei's did you try?  The single SQL statement, or the
Cursor logic?

When I mentioned the part about SETLL before READ I forgot to mention cycle
versus the READ :-)

Rob Berendt
--
"They that can give up essential liberty to obtain a little temporary
safety deserve neither liberty nor safety."
Benjamin Franklin



                    "Alan Novick"
                    <mida@pressmantoy.c       To:     <midrange-l@midrange.com>
                    om>                       cc:
                    Sent by:                  Fax to:
                    midrange-l-admin@mi       Subject:     Re: Can you do this 
in SQL
                    drange.com


                    01/30/2002 03:54 PM
                    Please respond to
                    midrange-l






Alexei:

You are right that your solution was not the best from a performance point
of view (yes I tried it) but I really enjoyed it, very impressive.  I use
SQL all the time and it's great to learn something new.  It's definitely
true that RPG is the right solution here but I these kinds of things give
an
idea of what is possible in other situations where it might be appropriate.
This is the best tip since I saw the bicycle icon in David Kahn's sig file!

I've also been taken aback by how the thread developed.  FWIW I'm a big fan
of OPNQRYF too, also since good old realease 8 of CPF.  Of course, when I
write the RPG program I will use the RPG cycle and level break indicators
but I don't want to start a big ruckus on the merits of that style :)

Thanks to all who responded.

Alan Novick
Pressman Toy Corporation
Enjoying the unsual biking weather in New Brunswick, NJ


----- Original Message -----
From: "Alexei Pytel" <pytel@us.ibm.com>
To: <midrange-l@midrange.com>
Sent: Tuesday, January 29, 2002 6:47 PM
Subject: RE: Can you do this in SQL



Just as an exersize - I can think of two ways of doing this in SQL:

1) in a single statement:

      update cus tu set rank =
      ( select count(*) from cus ts
         where tu.yr = ts.yr and tu.money <= ts.money )

which is not the best performer


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