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May this help you ? Let's assume TS is a Timestamp field and data file is TS DESC 2001-01-01-00.40.00.200000 a 2001-01-01-00.50.00.200000 b 2001-01-01-00.00.00.300000 c ******** Fine dati ******** By using select date(ts), avg(hour(time(ts))) hh , avg(minute(time(ts))) mm, avg(second(time(ts))) ss from temp/prova group by date(ts) you will get ....+....1....+....2....+....3....+....4....+....5....+.... DATE ( TS ) HH MM SS 01/01/01 0 30 0 ******** Fine dati ******** I hope this help. Sincerely Domenico Finucci Fiditalia , Milano, 02- 4301-2494 -----Messaggio originale----- Da: Joel Fritz [mailto:JFritz@sharperimage.com] Inviato: mercoledì 25 luglio 2001 17.14 A: 'MIDRANGE-L@midrange.com' Oggetto: RE: sql comparison between records I need to calculate the average duration between records for records that can be grouped by key. The real world application is mean time between clicks in a web site session. Regardless, it's kind of interesting in the abstract, IMHO. I was a big fan of Joe Celko's column when it used to appear in a now defunct freebie trade magazine. One of the recurring implicit themes of his column was the difference between the types of problems that were naturally suited to a procedural language and those that were better suited to SQL. > -----Original Message----- > From: thomas@inorbit.com [mailto:thomas@inorbit.com] > Sent: Tuesday, July 24, 2001 8:01 PM > To: MIDRANGE-L@midrange.com > Subject: Re: sql comparison between records > > > Joel: > > Since SQL is designed to handle sets of records, individual > record operations often aren't appropriate for it. But can > you clarify whether you actually need specific durations > between records or you want to use those durations only to > end up with an eventual average and the individual durations > will then be discarded? The second alternative might be > reasonably possible with SQL. > > Tom Liotta > > On Fri, 20 July 2001, Joel Fritz wrote: > > > > > How do you do this in SQL? > > > > I have a file ordered by key value and a timestamp. There > are multiple > > records for each key value. I want to find the difference > between time > > stamps of successive records and calculate the average > difference for a key > > value group. I know, it's easy in RPG. I'm not trying to measure > > programmer productivity. <g> > > -- > Tom Liotta > The PowerTech Group, Inc. > 19426 68th Avenue South > Kent, WA 98032 > Phone 253-872-7788 > Fax 253-872-7904 > http://www.400Security.com > > > ___________________________________________________ > The ALL NEW CS2000 from CompuServe > Better! Faster! More Powerful! > 250 FREE hours! Sign-on Now! > http://www.compuserve.com/trycsrv/cs2000/webmail/ > > > > > +--- > | This is the Midrange System Mailing List! > | To submit a new message, send your mail to MIDRANGE-L@midrange.com. > | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. > | To unsubscribe from this list send email to > MIDRANGE-L-UNSUB@midrange.com. > | Questions should be directed to the list owner/operator: > david@midrange.com > +--- > +--- | This is the Midrange System Mailing List! | To submit a new message, send your mail to MIDRANGE-L@midrange.com. | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. | To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. | Questions should be directed to the list owner/operator: david@midrange.com +--- +--- | This is the Midrange System Mailing List! | To submit a new message, send your mail to MIDRANGE-L@midrange.com. | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. | To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. | Questions should be directed to the list owner/operator: david@midrange.com +---
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