Re: Why Warning?

["Alexei Pytel" <pytel@xxxxxxxxxx>]

By definition, in C, specifying void f() means a function which does not
return any value, but can take any number of parameters of any type. So the
compiler is righ - this is not complete specification.

By contrast, in C++ void f() means function with NO parameters, which is
complete specification.

    Alexei Pytel



"Leif Svalgaard" <leif@leif.org>@midrange.com on 01/17/2001 06:39:53 AM

Please respond to MIDRANGE-L@midrange.com

Sent by:  owner-midrange-l@midrange.com


To:   <MIDRANGE-L@midrange.com>
cc:
Subject:  Re: Why Warning?



From: Leif Svalgaard <leif@leif.org>

> Folks, the following program works, but why do I get the warning?
>     1       |#include <stdio.h>
>     2       |void f();
>     3       |
>     4       |main() {
>     5       |  f();
> ===========>...a...
> *=Warning=========> a - CZM0185 Function f has not been prototyped prior
to
use.
>     6       |}
>     7       |
>     8       |void f() {
>     9       |  printf("hello\n");
>   10       |}


====> use f(void) instead of f(), but it is crummy warning text.


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