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Hello Bill, You wrote: >For X = A by B to C >A and B can be any positive or negative number >C must be any number greater than A >Which presents a problem with counting backwards. I'll grant you it's not the most intuitive form but the following code compiles and runs as expected: D i S 5I 0 C for i = 10 downto 0 by 1 C i dsply C endfor C seton LR Regards, Simon Coulter. «»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«» «» FlyByNight Software AS/400 Technical Specialists «» «» Eclipse the competition - run your business on an IBM AS/400. «» «» «» «» Phone: +61 3 9419 0175 Mobile: +61 0411 091 400 «» «» Fax: +61 3 9419 0175 mailto: shc@flybynight.com.au «» «» «» «» Windoze should not be open at Warp speed. «» «»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«»«» +--- | This is the Midrange System Mailing List! | To submit a new message, send your mail to MIDRANGE-L@midrange.com. | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. | To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. | Questions should be directed to the list owner/operator: david@midrange.com +---
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