|
Here's one that accepts a 8,0 YYYYMMDD as input. You can modify to your
standard date format. date_t and the constants are defined in the copy
member for the service program that this is part of.
*********************************************************************
*** Returns the day of the week of the date, if no date parameter is
*** passed then it returns the day of the week of the current day.
*** Constants are defined for the return value: SUN, MON, TUE, WED,
*** THU, FRI, SAT.
*********************************************************************
p day_of_week b export
d day_of_week pi 9
d date like(date_t) options(*nopass)
d const
d BASE_DATE c D'1992-12-05'
d diff s 6 0
d in_date s d
d remainder s like(diff)
d result s like(diff)
d temp_date s like(date_t)
c if %parms > 0
c *iso move date in_date
c else
c eval temp_date = today
c *iso move temp_date in_date
c endif
c in_date subdur BASE_DATE diff:*days
c diff div 7 result
c mvr remainder
c select
c when remainder = 0
c return SAT
c when remainder = 1
c return SUN
c when remainder = 2
c return MON
c when remainder = 3
c return TUE
c when remainder = 4
c return WED
c when remainder = 5
c return THU
c when remainder = 6
c return FRI
c endsl
*** Error subroutine
c *pssr begsr
c return *blanks
c endsr
p day_of_week e
> -----Original Message-----
> From: Klein Ron [SMTP:ron.klein@brctsg.com]
> Sent: Thursday, December 09, 1999 9:36 AM
> To: 'MIDRANGE-L (E-mail)
> Subject: Day of the week
>
> Hi all,
>
> Since we have a discusion going about the days of the month, how about a
> easy routine to find the day of the week? Any one have a solution?
>
> TIA
> Ron
>
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