Hmm... I'm missing something here. I have a date, say 10/13/1999 (todays date). You move the date to a variable Temp. Then you subtract one, doesn't that produce 10/12/1999 ? then you add one month so we get 11/12/1999, then you subtract one, and come up with 11/11/1999 ? What am I missing in this equation? Regards, Jim Langston Jon.Paris@halinfo.it wrote: > The following will supply the date of the last day of the month for the month >in > which InputDate falls. > > D InputDate D DATFMT(*ISO) > D Temp 3P 0 > > C Extract InputDate:*D Temp > C Eval Temp = Temp - 1 > C AddDur 1:*M InputDate > C SubDur 1:*D InputDate > > Thats's all there is to it!! > > +--- > | This is the Midrange System Mailing List! > | To submit a new message, send your mail to MIDRANGE-L@midrange.com. > | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. > | To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. > | Questions should be directed to the list owner/operator: firstname.lastname@example.org > +--- +--- | This is the Midrange System Mailing List! | To submit a new message, send your mail to MIDRANGE-L@midrange.com. | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. | To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. | Questions should be directed to the list owner/operator: email@example.com +---
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